Solutions for the Gearbox Designs from the Tutorial
First Design: B143-B172 E233-E280 G437-G542
Start with the gearbox finder:
B167 = 53
E278 = 53 * 53
G463 = 53 * 53 * 53
You can see that two of the 53 combinations can be shared: All outputs can use the first 53 combination, and E8 and G8 can share the second 53 combination. You can do this with only 5 medium gears total:
- A1: 1 4 (a spacer, then a 4-tooth)
- B2: 1 4 (same)
- C3: 5 3 (a 5-tooth, then a 4-tooth)
- B4: 3 (a 3-tooth, which completes your first 53 combo)
- B5: 3
- B6: 3 5 (starting your second 53 combo for the E8 and G8 outputs)
- B7: 3
- B8: 3 (these two just complete the line for the B167)
- C7: 1 3 (a spacer + a 3-tooth, completing your second 53 combo)
- D7: 1 3
- E7: 1 3
- E8: 1 3 (this completes your E278)
- F7: 1 3 5 (start of the third 53 for the G8 output)
- G8: 1 1 3 (completes the third 53 for the G8 output: G463)
Result: 14 small gears, 3 medium gears
Second Design: A206-A249 E131-E164 G275-G333
A240 = 65 * 653
E144 = 65 * 65
G288 = 65 * 65 * 653
I have chosen these ratios (they are not the cheapest possible for each output) because they can share the most things: 65 * 65 will be common for all outputs, then A branches off starting with a 3-tooth, E continues straight away from there, and G gets another 653 combination after that:
- A1 = 3 (the first gears are just to move the starting point to a better position)
- B1 = 3 4
- C2 = 1 4 6 (the 6-tooth starts the first 65 combination)
- C4 = 6 1 5 (finishing off the first 65, and starting the second 65 combination)
- C6 = 5 4 (the 5-tooth finishes the second 65 combination, the 4-tooth starts the straight line to E8)
- B7 = 3 1 4 (the 3-tooth finishes the 653 combination that the A output needs, it will also continue with a 4-tooth)
- A8 = 1 1 4 (this finishes the A240 output)
- D7 = 1 4 (continues the line to the E output)
- E8 = 1 4 (finishes the E144 output)
- E6 = 1 4 (to gain some space for the 653 combination that the G output still needs)
- F5 = 6 4 (the 6-tooth starts the 653 for the G output)
- F7 = 5 (continues the 653)
- G8 = 3 (finishes the 653 combination at the right spot)
Result: 13 small gears, 6 medium gears